JEE MAIN - Physics (2020 - 2nd September Morning Slot - No. 6)
A gas mixture consists of 3 moles of oxygen
and 5 moles of argon at temperature T.
Assuming the gases to be ideal and the oxygen
bond to be rigid, the total internal energy (in
units of RT) of the mixture is :
11
20
15
13
توضیح
U $$ = {{{f_1}} \over 2}{n_1}RT + {{{f_2}} \over 2}{n_2}RT$$
$$ = {5 \over 2}\left( {3RT} \right) + {3 \over 2} \times 5RT$$
$$ \therefore $$ U $$ = 15RT$$
$$ = {5 \over 2}\left( {3RT} \right) + {3 \over 2} \times 5RT$$
$$ \therefore $$ U $$ = 15RT$$